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Can someone help me please? find the limit of (x)/(e^(1/x) +1) for when x->0
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\[\lim x->0 for when (\frac{ x }{ e ^{\frac{ 1 }{ x }} +1})\]
the denominator goes to infinity lickety split the numerator goes to zero
do i need to do any algebra or is it pure speculation?
not sure what algebra you need here the fact that \[\lim_{x\to 0}x=0\] is more or less like whose buried in grant's tomb
as for \(e^{\frac{1}{x}}\) that limit is \(\infty\) if \(x\to 0^+\) as \(\lim_{x\to 0^+}\frac{1}{x}=\infty\)
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if \(x\to 0^-\) then \(\lim_{x\to 0^-}\frac{1}{x}=-\infty\) and so \[\lim_{x\to 0^-}e^{\frac{1}{x}}=0\]
oh i get it now.... thanks a bunch :D
yw
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