We perform the experiment "toss two dice." What is the probability of the event, "The sum of the faces equals 5"? Answer a) 4/36 b) 1/36 c) 1/6 d) 1/9
The sample space has 36 possible combinations of numbers. These can be set out in column form as follows: 6,6 5,6 4,6 3,6 2,6 1,6 6,5 5,5 4,5 3,5 2,5 1,5 6,4 5,4 4,4 3,4 2,4 1,4 6,3 5,3 4,3 3,3 2,3 1,3 6,2 5,2 4,2 3,2 2,2 1,2 6,1 5,1 4,1 3,1 2,1 1,1 Now you need to count the number of combinations where the sum is 5. Then divide that number by 36 to find the required probability.
is the final answer 1/9?
Did you count the number of combinations where the sum is 5?
Well, if you look at the top left hand pair of numbers which are 6, 6, you can see that 6 + 6 does not equal 5. However if you look at the bottom pair of numbers in the third column from the left, which are 4, 1, you can see that 4 + 1 = 5. therefore there is one pair of numbers in the third column that adds up to 5.
oh ok! i understand now. thank you!
is the final answer 4/36?
4/36 is correct. However 1/9 is the simplification of 4/36.
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