Ask your own question, for FREE!
Calculus1 16 Online
OpenStudy (anonymous):

Find the derivative of the given function

OpenStudy (anonymous):

f(x)= Root (x^2 +1)/Root (x^2-1)

OpenStudy (anonymous):

Flip the numerator with the denominator

OpenStudy (gorv):

\[\frac{ d(\frac{ u }{ v }) }{ dx }=\frac{ v*\frac{ du }{ dx } -u*\frac{*dv}{ dx }}{ v^2 }\]

OpenStudy (gorv):

use this

OpenStudy (anonymous):

how would you use that formula in this question?

OpenStudy (gorv):

u=numerator v=denominator

OpenStudy (gorv):

\[\frac{ df(x) }{ dx }=\frac{ \sqrt{x^2-1}*\frac{ d \sqrt{x^2+1} }{ dx } -\sqrt{x^2+1}*\frac{ d \sqrt{x^2-1}}{ dx }}{(\sqrt{x^-1} )^2}\]

OpenStudy (gorv):

can u do it now ??

OpenStudy (gorv):

sorry \[denominator=(\sqrt{x^2-1})^2\]

OpenStudy (gorv):

\[\frac{ d \sqrt{x^2+1} }{ dx }=\frac{1 }{ 2*\sqrt{x^2+1 }}* x\]

OpenStudy (anonymous):

is that the final answer?

OpenStudy (alekos):

should just be x/(sqrt(x^2+1))

OpenStudy (anonymous):

can you explain how?

OpenStudy (alekos):

the derivative of (x^2+1)^1/2 is (1/2)(x^2+1)^(-1/2) using the power rule but then we need to use the chain rule and multiply this by the derivative of x^2+1 which is 2x

OpenStudy (anonymous):

by chance can you explain using the equations?

OpenStudy (tkhunny):

@Astefank If you are in a calculus class, you should have studied algebra. Don't forget your algebra. Why are you asking for algebra help? Something very odd about that. @dwizz Don't post without showing your work. Where did you go?

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!