Find the derivative of the given function
f(x)= Root (x^2 +1)/Root (x^2-1)
Flip the numerator with the denominator
\[\frac{ d(\frac{ u }{ v }) }{ dx }=\frac{ v*\frac{ du }{ dx } -u*\frac{*dv}{ dx }}{ v^2 }\]
use this
how would you use that formula in this question?
u=numerator v=denominator
\[\frac{ df(x) }{ dx }=\frac{ \sqrt{x^2-1}*\frac{ d \sqrt{x^2+1} }{ dx } -\sqrt{x^2+1}*\frac{ d \sqrt{x^2-1}}{ dx }}{(\sqrt{x^-1} )^2}\]
can u do it now ??
sorry \[denominator=(\sqrt{x^2-1})^2\]
\[\frac{ d \sqrt{x^2+1} }{ dx }=\frac{1 }{ 2*\sqrt{x^2+1 }}* x\]
is that the final answer?
should just be x/(sqrt(x^2+1))
can you explain how?
the derivative of (x^2+1)^1/2 is (1/2)(x^2+1)^(-1/2) using the power rule but then we need to use the chain rule and multiply this by the derivative of x^2+1 which is 2x
by chance can you explain using the equations?
@Astefank If you are in a calculus class, you should have studied algebra. Don't forget your algebra. Why are you asking for algebra help? Something very odd about that. @dwizz Don't post without showing your work. Where did you go?
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