Write down the Pythagorean Identity sin^2 x +cos^2 x = 1. Divide each side of the equation by sin^2 x and describe the simplifications that can be done.

I know that the Pythagorean identity for sin2 x + cos2 x = 1 is sin2u + cos2u = 1 but I don't know where to go from there.

Question

Write down the Pythagorean Identity sin^2 x +cos^2 x = 1.  Divide each side of the equation by sin^2 x and describe the simplifications that can be done.  

I know that the Pythagorean identity for sin2 x + cos2 x = 1 is sin2u + cos2u = 1 but I don't know where to go from there.

anonymous · Answer

divide each term by $\sin^2(x)$ and see what you get 
first step is 
$$\frac{\sin^2(x)}{\sin^2(x)}+\frac{\cos^2(x)}{\sin^2(x)}=\frac{1}{\sin^2(x)}$$

anonymous · Answer

then rewrite each term in terms of a trig function
well, except for the first term which is evidently $1$

anonymous · Answer

I get the first step. But what is the format for a trig function?

anonymous · Answer

@mathmath333 @Algorithmic @gorv @Eagleeye13 @helpout3 @hugsnkisses @iGreen

triciaal · Answer

@sunshine201 are you suppose to prove  sin^2 x +cos^2 x = sin2u + cos2u ?

anonymous · Answer

I read the problem wrong. No. can you rewrite each term in terms of a trig function?

triciaal · Answer

|dw:1413298766095:dw|