hear is the question Determine the sum of the following geometric series. 1/64+1/16+1/4+...+1024
2^-6+...+2^10 The formula for geometric series: http://en.wikipedia.org/wiki/Geometric_progression#Geometric_series To shift the sequence, change 'a'
\(\large\tt \color{black}{\dfrac{a(r^n-1)}{r-1}}\) \(\large\tt \color{black}{\text{where a = first term and r is common ratio}}\)
okay
do you know how to find the common ratio
its \[\frac{ 1 }{ 16 }\div \frac{ 1 }{ 64}\] its \(\large\tt \color{black}{\text{2nd term divided by first term or }}\) \(\large\tt \color{black}{\text{3rd term divided by 2nd term or }}\) \(\large\tt \color{black}{\text{4th term divided by 3rd term }}\)
oh okay
\(\large\tt \color{black}{\text{and n = number of terms in series}}\)
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