Question

Two dice are thrown simultaneously. Given that sum of the numbers is NOT more than 5, what is the probability that sum is more than 3?

Answer 1

The sample space has 36 possible combinations of numbers. These can be set out in column form as follows: 6,6 5,6 4,6 3,6 2,6 1,6 6,5 5,5 4,5 3,5 2,5 1,5 6,4 5,4 4,4 3,4 2,4 1,4 6,3 5,3 4,3 3,3 2,3 1,3 6,2 5,2 4,2 3,2 2,2 1,2 6,1 5,1 4,1 3,1 2,1 1,1 Now you need to count the number of occurrences where the sum of the numbers in a pair is either 4 or 5. Let this total number of occurrences be x.
Next count the total number of occurrences where the sum of the numbers in a pair is five or less than 5, and let this total number of occurrences be y.
The required probability is found from x/y.

Answer 2

I got it now lol thanks tho

Answer 3

You're welcome :)

Answer 4

Sorry about the loss of formatting The table is as follows:
The sample space has 36 possible combinations of numbers. These can be set out in column form as follows:
6,6 5,6 4,6 3,6 2,6 1,6
6,5 5,5 4,5 3,5 2,5 1,5
6,4 5,4 4,4 3,4 2,4 1,4
6,3 5,3 4,3 3,3 2,3 1,3
6,2 5,2 4,2 3,2 2,2 1,2
6,1 5,1 4,1 3,1 2,1 1,1