Question

Can someone check this to see if I'm doing it correctly?

1. A chemical reaction is carried out using a 42.65-g sample of lead(II) nitrate, Pb(NO3)2.

a. Calculate the molar mass of lead(II) nitrate.

(1*207.2) + (2*14.0067) + (6*15.9994) = 331.2098 grams/mole of lead(II) nitrate

b. Calculate the number of moles of lead(II) nitrate in the sample.

n = m/M = 42.65/331.21 = 0.13

c. Calculate the number of formula units of lead(II) nitrate in the sample.

0.13*6.022*10^23 = 0.783*10^23