The Kp for the reaction below is 1.49 × 108 at 100.0°C:

CO(g) + Cl2(g) → COCl2(g)

In an equilibrium mixture of the three gases, PCO = PCl2 = 2.22 × 10-4 atm. The partial pressure of the product, phosgene (COCl2), is ________ atm.
A) 7.34
B) 3.02 × 1015
C) 3.31 × 10-16
D) 3.31 × 104
E) 6.67 × 1011
Answer: A

Question

The Kp for the reaction below is 1.49 × 108 at 100.0°C:

	CO(g) + Cl2(g)  →  COCl2(g)

In an equilibrium mixture of the three gases, PCO = PCl2 = 2.22 × 10-4 atm. The partial pressure of the product, phosgene (COCl2), is ________ atm.
A) 7.34 
B) 3.02 × 1015 
C) 3.31 × 10-16 
D) 3.31 × 104 
E) 6.67 × 1011 
Answer:  A

ashley1nonly · Answer

i dont know what i am looking for here

anonymous · Answer

kk 1 sec

anonymous · Answer

kk it was the same way we did the 1st problem
but this time it is kp, so kp=(COCl2)/(CO)(Cl2)

ashley1nonly · Answer

and then we solve for COCl2

1.48*10^=x/(2.24*10-4)^2

anonymous · Answer

Perfect!

ashley1nonly · Answer

ok let me get one more question

anonymous · Answer

kk