Question

Factor for solutions:
X^3 -64=0

Is it X=4. I'm just making sure if it is?

Answer 1

yes!!

X^3 -64=0
x^3 = 64
x^3 = 4 x 4 x 4 = 64
x = 4

Answer 2

here u will get 3 solutions including x=4 and two imaginary solutions

Answer 3

\(\large\tt \color{black}{x^3-4^3=0}\)

apply the formula

\(\large\tt \color{black}{a^3-b^3=(a-b)(a^2+ab+b^2)}\)

Answer 4

Would I get 3 solutions for 2x^2+10x+8 or just 2 solutions

Answer 5

for that i got (X+1) (x+4)

Answer 6

for this 2x^2+10x+8 it will be two as the power of x is 2

Answer 7

would it be (X+1) (x+4)

Answer 8

\(\huge\tt \color{black}{= 2(x+1) (x+4)}\)

Answer 9

Oh okay

Answer 10

Now I have 1 more. For this problem, X^3+5X^2+6X=0. Would it be 3 solutions and if so would it be X=0, -2, -3

Answer 11

u can check it urself by putting each solution in the equation if
it is equal to zero then u r correct

Answer 12

the power of x is three so here will be three solutions

Answer 13

[k great thanks

Answer 14

Sorry but for X^3 -64=0, Would the solutions be X= 4, 2-2i√ 3, 2+2i√ 3

Answer 15

yes of cos it would be