Question

) A reaction is found to have an activation energy of 38.0 kJ/mol. If the rate constant for this reaction is 1.60 × 102 M-1s-1 at 249 K, what is the rate constant at 436 K?
A) 2.38 × 105 M-1s-1
B) 1.26 × 103 M-1s-1
C) 7.94 × 104 M-1s-1
D) 4.20 × 105 M-1s-1
E) 3.80 × 104 M-1s-1
Answer: D

Answer 1

we will use
lnk2/k1=( Ea/R)(1/t1-1/t2)

Answer 2

kk 1 sec

Answer 3

ok

Answer 4

Im working in a group preparing for my chemistry exam and my group wants to just praise to you for helping us understand these problems. we have a test on Monday and you made everything so simple and we will pass now lol

Answer 5

Im happy to hear that I could help, and you will all do excellent

Answer 6

kk I got this one

Answer 7

lets do it

Answer 8

1. convert 38.0kj to joules so 38*10^3Joule R=constant 8.3145

2.equation 1.60^2*e^(38Jmole*8.3145)*(249-436)

3. 1.60^2e^(7.87233)=4.20*105

Answer 9

what variable are we solving for so i can mentally see where you are going with the numbers

Answer 10

kk 1 sec

Answer 11

we are solving for k2

Answer 12

working it out to see if i can get the answer

Answer 13

1.) ln(k2/k1)=(Ea/R)(t1-t2)

2.) ln(1.60*10^2/k1)=(38*10^3)(249-436)

3.) ln(1.60*10^2/k1)(=(65.4544)

4 k1(1.60*10^2) =65.4544/ln

5.k1=1.60*10^2*e^65.4544= 4.20*105

Remember when dividing by ln, make it e^

Answer 14

so we were solving for k1 or k2

Answer 15

basically just use algebra rules

Answer 16

okay that makes sense now

Answer 17

okay we have one more which is similar to this one

Answer 18

is it making sense, sorry I am a slow typer

Answer 19

yes the problem we had was getting rid of the ln. we had no clue

Answer 20

also it is easier to fully solve the right side of the equation and just have one number instead of all the equations

Answer 21

then once we do that we can take the e to get rid of the ln and the multiply to get rid of the k1 which leaves us with k2

Answer 22

Basically for this problem, divide the right side with ln (ea*ti-t2) make it say e^value

Answer 23

yes

Answer 24

im going to post the last question that we have for you and that will complete us lol

Answer 25

yes k2 is what you are finding k1=1.60*10^2

Answer 26

kk sounds good, did this problem make sense

Answer 27

at first it didnt because i didnt know what we were looking for and i got lost in all of the different variables but the way you broke it down shows all of the steps i needed.

Answer 28

kk awseome!