Question

51) If the activation energy for a given compound is found to be 42.0 kJ/mol, with a frequency factor of 8.0 × 1010 s-1, what is the rate constant for this reaction at 298 K?
A) 2.9 × 10-4 s-1
B) 7.4 × 10-4 s-1
C) 1.4 × 109 s-1
D) 4.6 × 10 5 s-1
E) 3.5 × 103 s-1
Answer: E

Answer 1

Ok this one is similar i think i can do this, i just need to know what variable are we looking for

Answer 2

kk

Answer 3

lnk1/k2= (Ea/r)(1/t1-1/t2)

Answer 4

yes, and do not worry about the 1 over the temperatures

Answer 5

do we not need the 1/t for this equation

Answer 6

no i mean. for any of these questions keep the temp, but get rid of the 1 over them

Answer 7

wouldnt that make the answer incorrect

Answer 8

??

Answer 9

No, I just know in chem 2 you can leave it out, but you can do what is more better for you

Answer 10

ok. so in this problem what variable are we solving for

Answer 11

k2

Answer 12

really!

Answer 13

we only have t1 so what do we do for t2

Answer 14

0-298k, let me work it out

Answer 15

ok

Answer 16

do you have another equation with frequency factor

Answer 17

yes let me see

Answer 18

kk

Answer 19

If the activation energy for a given compound is found to be 103 kJ/mol, with a frequency factor of 4.0 × 1013 s-1, what is the rate constant for this reaction at 398 K?
A) 1.2 s-1
B) 8.2 s-1
C) 3.9 × 1010 s-1
D) 1.7 × 1010 s-1
E) 2.5 × 107 s-1
Answer: A

Answer 20

forgot i have to start another question

Answer 21

kk

Answer 22

what formula did your teacher give you

Answer 23

i posted the next question

Answer 24

kk 1 sec

Answer 25

we can use the same one or we can use


k=Ae^(Ea/RT)

Answer 26

kk awseome this is what we need

Answer 27

ok

Answer 28

so we are finding k
1.) k=4.0*1013e^(10300)/(8.314)(398)= about 1.2

Answer 29

understand?

Answer 30

so on the other problem we need to use this formula

Answer 31

yes but the answer is 3.5

Answer 32

I did the other problem

Answer 33

now, il do the one that equals 3.5

Answer 34

ok let me try this one

Answer 35

kk

Answer 36

got the right answer, THANK YOU SOOOOO MUCCHHH, MUCCHHH LOVE FROM FLORIDAAAAAA. IM GOING TO FINALLY GET AN A. BLESS YOUR SOUL AND THANKS FOR SPENDING YOUR TIME

Answer 37

ALL OUT OF QUESTIONS NOW

Answer 38

No problem, Im glad you understood it all, good luck on your exam, feel free to ask questions any time

Answer 39

thank you so much, i will be your first fannnn, everyone needs at least one fan

Answer 40

Sounds good, thanks
Remember watch your units

Answer 41

always