Question

Can someone help me with this? I got to 63.2 times 1 mol HCl/36.461 = 1.7334

Consider the complete reaction of 63.2 g of HCl with excess oxygen gas. What mass of chlorine gas product forms?
4 HCl(g) + O2(g) → 2 H2O(l) + 2 Cl2(g)

Answer 1

First find the moles of HCl. For this you divide 63.2 g by the molar mass of HCl that you find on the periodic table.
After that you see that the ratio of HCl:CL2 is 4:2, or 2:1. Therefore moles of Cl2 equal half of the moles of HCl.
Now that you have the moles of Cl2 , convert to grams using the molar mass

Answer 2

So 61.45?

Answer 3

I didnt do the math, but if you followed the procedure then it is correct

Answer 4

Ok, thanks.

Answer 5

no problem