Question

In a calorimetry experiment, it was determined that a 92.0 gram piece of copper metal released 1860 J of heat to the surrounding water in the calorimeter (qcopper = −1860 J). If the final temperature of the copper metal-water mixture was 25.00°C, what was the initial temperature of the copper metal? The specific heat of copper is 0.377 J/(g°C)

Answer 1

q=smΔT

Answer 2

\[q=sm \Delta T\]

Answer 3

\[\frac{ q }{ sm }=\Delta t\]

Answer 4

plug in the numbers and solve for delta T