Question

Can someone please tell me the integral of:

Answer 1

\[\int\limits_{0}^{\pi/2}y^2\sin(x)\]

Answer 2

Well, not the answer, but the steps to get the answer

Answer 3

You have a mixture of variables there

Answer 4

we integrating w.r.t x or y?

Answer 5

Sorry, this is multivariable calc so I only put in the part i needed help with. Wrt to x

Answer 6

If you are integrating w.r.t x you treat y like a constant

Answer 7

\[\int\limits_{-3}^{3}\int\limits_{0}^{\pi/2}(y+y^2cosx)dxdy\]

Answer 8

do you know how to integrate sin(x) w.r.t x?

Answer 9

Did I integrate \[y^2cosx\] properly?

Answer 10

\[\int\limits_{-3}^{3}[yx+y^2\sin(x)]|_{x=0}^{x=\frac{\pi}{2}} dy \]

Answer 11

Okay, so I'm on the right track?

Answer 12

I don't know where you got integrating y^2*sin(x) w.r.t x from

Answer 13

Anyways you need to evaluate the limit part
then integrate w.r.t y

Answer 14

I probably didn't write it properly, but it looks like we're on the same path. Thank you.