find dy/dx by implicit differentiation sqrt (x+y) = (5+x^2y^2)
will give medal & fan ... but i want to understand the steps too...
@iambatman @phi @PaxPolaris @mathsails
@Yttrium
someone help me :'(
\[\LARGE \sqrt {x+y} = (5+x^2y^2)\] Ok try your best to take the derivative and I'll help you.
Well I'm not going to wait around all day, I can help you out and I know the answer but I won't help someone who won't help themselves first.
i have something.... \[\frac{ 1 }{ 2\sqrt{x+y} }*(1+\frac{ dy }{ dx })=2x*2y*\frac{ dy }{ dx }\]
except that was wrong
there is a bit of algebra for this one. How far did you get? did you find the derivative of the left side? what did you get ?
1/2 (x+y)^-1/2
and at the end of that I would add d/dx
that's what i'm trying to get to one side to solve for
I have to go on the skytrain now
:'(
\[ \frac{d}{dx} u^\frac{1}{2} = \frac{1}{2}u^{-\frac{1}{2}} \frac{d}{dx} u \] you have the first part, but you need the second part \[ \frac{d}{dx} u = \frac{d}{dx} (x+y) \]
this is due in 40 mins oh dear lord
the left side is \[ \frac{1}{2 \sqrt{x+y}} \cdot (1 + \dot{y} )\]
the right side is x^2 d/dx (y^2) + y^2 d/dx(x^2)
solve for \( \dot{y} \)
for the right side you should get \[ 2 x^2 y \ \dot{y} + 2 x y^2 \]
now it's algebra, solve for \( \dot{y} \) \[ \frac{1}{2 \sqrt{x+y}} \cdot (1 + \dot{y} ) = 2 x^2 y \ \dot{y} + 2 x y^2 \]
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