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Mathematics 14 Online
OpenStudy (anonymous):

can someone help me with this ;] a ball measures 1.5 = t for a drop of 1.88 m the picture is attached https://db.tt/cYRnDpiX

OpenStudy (kohai):

So are you looking for the acceleration?

OpenStudy (anonymous):

yeah

OpenStudy (anonymous):

how do you do that?

OpenStudy (kohai):

Alright, I'll help you in the manner I learned in physics. You first need to find the velocity of this, which is V=d/t Velocity = distance/time What is that?

OpenStudy (anonymous):

1.25 m/s?

OpenStudy (anonymous):

now what?

OpenStudy (kohai):

Why are there negatives on the exponent... lol. The unit for acceleration is m/s^2

OpenStudy (kohai):

Oh. Oh I see. It's asking about acceleration due to gravity. The acceleration due to gravity is always -9.8m/s^2

OpenStudy (yttrium):

Well, generally in physics problems like this, g is always equal to 9.81 m s^-2, but to satisfy the conditions given by the problem we have to use another value for g. we can use \[h = V_{o}t \pm \frac{ 1 }{ 2 } g t^2\] (a derived kinematic equation) @t = 1.5, h = 1.88, Vo = 0, since it is a free-fall Hence, \[1.88 = +0.5 g(1.5)^2\] g = 1.67 m s^-2 (approximately)

OpenStudy (yttrium):

Note: The sign is positive because the motion direction is the same as the gravitational direction.

OpenStudy (yttrium):

and to answer you @kohai ms^-2 is the same as m/s^2. Recall your math, negative exponents means a base reciprocal

OpenStudy (perl):

great explanation

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