can someone help me with this ;] a ball measures 1.5 = t for a drop of 1.88 m the picture is attached https://db.tt/cYRnDpiX
So are you looking for the acceleration?
yeah
how do you do that?
Alright, I'll help you in the manner I learned in physics. You first need to find the velocity of this, which is V=d/t Velocity = distance/time What is that?
1.25 m/s?
now what?
Why are there negatives on the exponent... lol. The unit for acceleration is m/s^2
Oh. Oh I see. It's asking about acceleration due to gravity. The acceleration due to gravity is always -9.8m/s^2
Well, generally in physics problems like this, g is always equal to 9.81 m s^-2, but to satisfy the conditions given by the problem we have to use another value for g. we can use \[h = V_{o}t \pm \frac{ 1 }{ 2 } g t^2\] (a derived kinematic equation) @t = 1.5, h = 1.88, Vo = 0, since it is a free-fall Hence, \[1.88 = +0.5 g(1.5)^2\] g = 1.67 m s^-2 (approximately)
Note: The sign is positive because the motion direction is the same as the gravitational direction.
and to answer you @kohai ms^-2 is the same as m/s^2. Recall your math, negative exponents means a base reciprocal
great explanation
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