FAN & MEDAL!!! Solve by substitution. y = negative-2 4x − 3y = 18 (0, negative-2) (3, negative-2) (negative-2, negative-2)
@J-bird
im here
k, igreen isn't
good
I have a couple questions
its 3,negative 2
Which of the following is the solution of the given system of equations? -negativex + y − z = 14 2y + z = negative-12 y = 2 (4, 2, 16) (4, 2, negative-16) (14, 2, negative-16) (negative-4, 2, 21)
what grade are you in BTW
11th, it's pathetic I don't know algebra
i did algebra last year and im in 9th
you're smart, what's the answer Which of the following is the solution of the given system of equations? -negativex + y − z = 14 2y + z = negative-12 y = 2 (4, 2, 16) (4, 2, negative-16) (14, 2, negative-16) (negative-4, 2, 21)
why are there 3 digits for answers?? i only see z and y
oh nvm i see it
cause there's a -x
ok so z=8 y=2 with those number can you figure out x??
and stuff
get out of here reaves im trying to help him
hmm hang on a sec
not really, I don't really have time , I have like 4 more Q's and only 7 mins
z= -16
Solve by back substitution. x + 2y + z = 4 x + z = 4 z = 2 (3, 1, negative-2) (2, 0, 2) (negative-1, 0, negative-2) (2, 1, 2)
z and x both equal 2
let me find y a sec
its 2 0 2
Solve by back substitution. y = negative-2 x + y = negative-4 x + y + 5 = z (0, negative-2, 0) (negative-2, negative-2, 1) (2, negative-2, 0) (1, negative-2, 1)
-2 -2 0
CAN YOU SHOW WORK FOR THIS Solve the system by substitution. negative-3 x − 3 y = 3 y = negative-5 x − 17
one sec
sorry taking so long this one is harder XD
-3x and -3y. to pass off showing your work, just substitute them into the equation, thats what i did and aced algebra
If you get the solution 12 = 5 there is no solution to the system of equations. True False
@J-bird
true
last one If you get the solution 1 = 9, there are infinitely many solution to the system of equations. True False
false
0=0 is infinitely many solutions
thanks
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