Question

What is the equation of the line which includes points (0, 3) and (4, 5)? Please help!

Answer 1

gradient = y2-y1/x2-x1

Answer 2

5-3/4-0

Answer 3

1/2 is the answer

Answer 4

y-y1= slope(x-x1)

Answer 5

slope you calculated as = 1/2
and put in any point in place of x1 and y1

Answer 6

The slope-intercept equation of a line is:
\(y = mx + b\)

Answer 7

In this problem we are given two points, (0, 3) and (4, 5), so we can find the slope, m.
\(m = \dfrac{y_2 - y_1}{x_1 - x_1} = \dfrac{5 - 3}{4 - 0} = \dfrac{2}{4} = \dfrac{1}{2}\)

Answer 8

i already said that :/

Answer 9

Now we can add the slope to the slope-intercept form of the equation.
\(y = \dfrac{1}{2}x + b\)
We need to find b.

Answer 10

Now we use either one of our given points, and we plug in the x- and y-coordinates for x and y, respectively, in the equation to find b. Let's use point (0, 3):

\(3 = \dfrac{1}{2}(0) + b\)

\(b = 3\)

Now that we know b = 3, we just replace b with 3 in the slope-intercept equation:

\(y = \dfrac{1}{2}x + 3\)

Answer 11

@Gaelle_1
You did calculate the slope correctly, but you stopped there, and said that was the answer. The question is asking for the equation of the line, not just the slope.

Answer 12

Actually, the answer was indeed only y=1/2x plus 3 I forgot about this and got it lol

Answer 13

@mathstudent55
yeah sorry :P