When heated, calcium carbonate decomposes to yield calcium oxide and carbon dioxide gas via the reaction CaCO3(s)→CaO(s)+CO2(g) What is the mass of calcium carbonate needed to produce 75.0L of carbon dioxide at STP?

Question

anonymous · Answer

First, calculate the amount of $CO_2$ in moles.
The reaction $CaCO_3\rightarrow CaO+CO_2$ shows that to produce 1 mole of $CO_2$, we need 1 mole of $CaCO_3$. Use the amount of $CO_2$ to calculate the mass of $CaCO_3$.