Question

solve by factoring x^3 - 64=0

Answer 1

x^3 - 64=0
x^3 = 64
\[x \sqrt[3]{64} = 4\]

Answer 2

\[x = \sqrt[3]{64} = 4\]

Answer 3

has to be by factoring you have to use SOAP then use quadratic formula

Answer 4

difference of cubes... has 3 roots, 1 real and 2 complex

Answer 5

\(\tt \color{black}{\text{use formula}}\)

\(\large\tt \color{black}{a^3-b^3=(a-b)(a^2+ab+b^2)}\)

Answer 6

i used the formula. now i have to find the Zeros (answers)

Answer 7

\(\tt \color{black}{\text{u will get one solution x=4 thats clear}}\)

\(\large \tt \color{blue}{for ~~x^2+4x+16=0}\)

\(\tt \color{black}{\text{use formula}}\)

\(\large \tt \color{blue}{x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}}\)