Estimate the heat of neutralization of H3PO4 in kJ/mol given these data: Heat transferred = 2.2 x 102 J Moles of H3PO4 = 1.5 x 10−3 mol Moles of NaOH = 5.0 x 10−3 mol

Question

Estimate the heat of neutralization of H3PO4 in kJ/mol given these data:  Heat transferred = 2.2 x 102 J  Moles of H3PO4 = 1.5 x 10−3 mol  Moles of NaOH = 5.0 x 10−3 mol

anonymous · Answer

1.) write out the balance equation
      3NaOh+H3PO4->Na3PO4+3H2O

2.) You are given everything needed to calculate
     q=heat transfer=2.2*10^2, H3PO4 moles= 1.5*10^-3, NaOH moles=5.0*10^-3

3.) equation is deltaHneutraliztion=q/Moles of limiting reagent
     H3PO4 is limiting reagent because lowest moles, and is used up first

4.) Now plug in variables
     DeltaH=2.2*10^2(1.5*10^3)= 146.67kj/mole
     Notice we had to convert J to kj,