Help with precal please
Well have you consider pluggin in the endpoints yet
How can you see the endpoints
f is continuous on [a,b] and f(a) and f(b) have opposite signs then there exist c in [a,b] such f(c)=0. Or if you had a<=k<=x<=d<=b and you have f(k) and f(d) are opposite in sign there there exists c in between [a,b] such that f(c)=0
oh the abcd?
[a,b] a is the left endpoint and b is the right endpoint
soh for b since its -3 and 3 there is at least one zero?
So example f(x)=x^3 is continuous on [-2,3] and f(3)=3^3=27 and f(-2)=(-2)^3=-8 As you see one output is positive and the other output is negative so there is c between -2 and 3 such that f(c)=0
|dw:1413405538647:dw| Since f is continuous we have to connect these dots and there is no holes between -2 and 3 because again we know f is continuous on [-2,3] |dw:1413405586803:dw| As you see the graph has to cross the x-axis
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