Question

What is the antiderivative of cos^3(x)+4/cos^2(x)?

Answer 1

@amistre64

Answer 2

can you clean up the notation, its a bit vague at the moment what the function is spose to be

Answer 3

\[\frac{a^3+b}{a^2}\]or
\[a^3+\frac{b}{a^2}\]

Answer 4

it is \[\int\limits \frac{ \cos ^{3}x+4\ }{\cos ^{2} x }\]

Answer 5

split the fraction

Answer 6

wow im having really bad connection sorry about this

Answer 7

its the site itself, its been broken for a while now

Answer 8

so \[\cos x + \cos ^{-2}x\] ?

Answer 9

pretty much cos^(-2) = sec^2 right?

Answer 10

oh, wow that's really easy then

Answer 11

\[\int\limits \cos x+4\ \sec ^{2} x \]

yes, it is rather simple :)

Answer 12

so then integral of that is -sinx + tanx

Answer 13

-sinx+4tanx

Answer 14

yep, dont forget the constant

Answer 15

+C

Answer 16

thatll do it

Answer 17

thank you!

Answer 18

yw