Ask your own question, for FREE!
Mathematics 15 Online
OpenStudy (anonymous):

I need help on these questions. ( Algebra II)

OpenStudy (anonymous):

Here's the questions!

OpenStudy (anonymous):

Someone help me please!!

OpenStudy (anonymous):

Anybody there!

OpenStudy (anonymous):

for the first one, plug set g(x)=x, then plug that into f(x) and simplify

OpenStudy (anonymous):

so (6x)^2+3

OpenStudy (anonymous):

Oh ok, and then?

OpenStudy (anonymous):

simplify that, and you have your answer

OpenStudy (anonymous):

Oh

OpenStudy (anonymous):

Ok

OpenStudy (anonymous):

think of the equation as (g(x))^2+3

OpenStudy (anonymous):

and plug the value of g(x) into the function, which is 6x

OpenStudy (anonymous):

Ok, Got it! And for the next question?

OpenStudy (anonymous):

same thing, but with f

OpenStudy (anonymous):

you take f(x)=10-x, and make it into 10-f(x)

OpenStudy (anonymous):

then since f(x)=10-x, you plug that into 10-f(x)

OpenStudy (anonymous):

which gives you simply x

OpenStudy (anonymous):

And add 3 into (x), Right?

OpenStudy (anonymous):

yup :)

OpenStudy (anonymous):

so the answer is?

OpenStudy (anonymous):

7

OpenStudy (anonymous):

it may seem like 7 but it's not

OpenStudy (anonymous):

yu're not substituting x=3 into the original function

OpenStudy (anonymous):

oh

OpenStudy (anonymous):

you have to plug f(x) into the original f(x), if that makes sense

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

f(x)=10-x, and x=f(x). So you plug it in, which is 10-(10-x).

OpenStudy (anonymous):

this simplifies to x

OpenStudy (anonymous):

Oh ya!

OpenStudy (anonymous):

so then you plug x=3 into that equation

OpenStudy (anonymous):

which gives you...?

OpenStudy (anonymous):

3

OpenStudy (anonymous):

yup! yay! good for you.

OpenStudy (anonymous):

yay! Thanks! Your great! :)

OpenStudy (anonymous):

i'm glad I could help!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!