Question

Can someone help me please?

If 75.0 g of silderite ore (FeCO3) is heated with an excess of oxygen, 45.0 g of ferric oxide (Fe2O3) is produced.

4feCO3(s) + O2(g) -> 2fe2O3(s) + 4CO2(g)

what is the percent of yield of this reaction?

Answer 1

about 90%, do you want me to explain

Answer 2

yes because i don't know how to figure it out

Answer 3

kk 1 sec

Answer 4

thank you

Answer 5

np kk

Answer 6

1.) our reagent FeCO3-
mass-116, 0.65(75g/116g/moles)

2.) 1moles Fe2O3 for every 2mole FeCO3
Fe2O3=.325moles

3.) Get both mass of Fe2CO3 and FeCO3
45, 160 grams

4.) 45/160grams*100=about 90%

Answer 7

make sense?

Answer 8

oh yes! it does make sense:)

Answer 9

kk awseome, I can show more steps, if not making, sense, but if feel free to ask for more help if you need

Answer 10

Ok thank you:)

Answer 11

np

Answer 12

so are you ok with this problem

Answer 13

yes i am

Answer 14

kk awseome!