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A conical tank (with vertex down) is 12 feet across the top and 18 feet deep. If water is flowing into the tank at a rate of 18 cubic feet per minute, find the rate of change of the depth of the water when the water is 10 feet deep.
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divide by 12
I get to dV/dt=1/3pi(10)^2dh/dt but the answer I get after simplifying is not one of the answer choices
correct
wouldnt it be dV/dt=1/9pi(10)^2 dh/dt?
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