Percent yield:

In the equation
2 CO2 (g) + 4 KO2 - 2 K2CO3 (s) + 3 O2 (g)

If 701 g of O2 is produced, what is your percent yield for the equation?

I have already found that KO2 is the limiting reagent, however, I'm not sure how to find the percent yield.

*** You start out with 3.0kg of KO2 & 1kg of CO2

Question

Percent yield:

In the equation 
2 CO2 (g) + 4 KO2 -> 2 K2CO3 (s) + 3 O2 (g)

If 701 g of O2 is produced, what is your percent yield for the equation?

I have already found that KO2 is the limiting reagent, however, I'm not sure how to find the percent yield.

*** You start out with 3.0kg of KO2 & 1kg of CO2

preetha · Answer

gnet, looks like you are missing some info.  In general % yield = Actual Yield /Theoretical Yield 
So 701 g is the actual yield.  But to calculate Theoretical yield you need to know how much reactants you have in the reaction pot.

anonymous · Answer

Sorry I added it the missing information, thanks for pointing it out!