Consider the curve x^3 + 3 xy + y^3 = 5 The equation of the tangent line to the curve at the point (1,1) has the form y = mx + b where m = and b =
Well we first need to differentiate both sides of the equation in your first line.
We do that to so we can find m right? Because the slope would be the derivative
Yes.
The 5 goes away obviously then, let me see if I can figure out how to do the other side!
Can you help me differentiate the x^3 + 3 xy + y^3 without giving it away completely to me? :P
Well I think you can differentiate x^3 w.r.t. x pretty easily using power rule
3(xy) 3 is a constant multiple so use constant multiple rule 3(xy) xy is a product so use product rule
Okay, so just because it's 3 sums added together doesn't effect the sum rule? I've only seen it used with 2 that's why I got confused
\[\frac{d}{dx}(xy)=y \frac{d}{dx}(x)+x \frac{d}{dx}(y) =y \frac{dx}{dx}+x \frac{dy}{dx}=y(1)+x \frac{dy}{dx} \\ \frac{d(xy)}{dx}=y+x \frac{dy}{dx}=y+xy' \]
\[C \cdot \frac{d(xy)}{dx}=C(y+xy')\] where C is a constant
Let me work on this I think I get it! Thanks for your help!
Is it wrong to use 3x when doing the product rule instead of using the constant rule? Sorry for all the questions I'm just trying to figure out this stuff completely as I have a midterm tomorrow hahaha
But you still need to use product for (3x)*y
Yes I got 3x+3y after doing the product rule
:(
derivative of y is y'
(3x*y)'=(3x)'y+(3x)(y)' =3y+(3x)y' =3y+3xy'
Cant use power rule on that y'? :O
chain rule
y is a function of x so that is why we say derivative of y w.r.t x is y'
Ohhhhh okay!!!!! Yes
Thanks a ton I got it from here!
Join our real-time social learning platform and learn together with your friends!