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Mathematics 14 Online
OpenStudy (anonymous):

medal

OpenStudy (anonymous):

OpenStudy (anonymous):

This is where you use Pythagorean theorem. Notice how the looks like a right triangle(a.k.a has an angle of 90 degrees)?

OpenStudy (anonymous):

The equation is \[c ^{2}= a ^{2} + b ^{2}\]

OpenStudy (anonymous):

c is the side of the triangle across from the right angle. in this case c = 16km

OpenStudy (anonymous):

Then is doesn't really matter what other side we call 'a' and what side we call 'b'. But, in the case the pictures says b = 13km

OpenStudy (anonymous):

So now we are going to take our c = 16 and b = 13 and put them into our equation \[c ^{2} = a ^{2} + b ^{2}\]

OpenStudy (anonymous):

So, \[16^{2} = a ^{2} + 13^{2}\]

OpenStudy (anonymous):

Using our calculator we get 16^2 = 256 and 13^2 = 169 Then we put those values into the equation.

OpenStudy (anonymous):

\[256 = a ^{2} + 169\]

OpenStudy (anonymous):

Now we want all the constants on one side. So we move the 169 to the over side of the equal sign by subtracting 169 from both sides. We then get:

OpenStudy (anonymous):

\[87 = a ^{2}\]

OpenStudy (anonymous):

Now the final step is to take the square root of both sides to get rid of the 2 above the 'a' Our final answer is now:

OpenStudy (anonymous):

\[a = 9.33\]

OpenStudy (anonymous):

Thanks!

OpenStudy (anonymous):

np

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