Mathematics
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OpenStudy (anonymous):
what is the derivative of x^2(2x+1)^(1/2)
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OpenStudy (anonymous):
\[x ^{2}(2x1)^{1/2}\] This is the equation
OpenStudy (anonymous):
(2x+1)
OpenStudy (anonymous):
yes that is the equation
OpenStudy (anonymous):
Do you know the product rule?
OpenStudy (anonymous):
yes I do
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OpenStudy (anonymous):
OK so we are looking at x^2 times (2x+1) ^ 1/2 correct?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
would I use the product rule?
OpenStudy (abdullah1995):
this is a simple product rule question. if you want, expand it all out so it becomes a power rule
OpenStudy (anonymous):
Yes use the product rule.
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OpenStudy (abdullah1995):
product rule = f'(g)(fx)+f(g)f'(x)
OpenStudy (abdullah1995):
in this case
x^2 => f(g)
(2x+1)^(1/2) =>f(x)
OpenStudy (anonymous):
oh ok thank you so much!
OpenStudy (abdullah1995):
if you are still having trouble let me know and we can go over it step by step
OpenStudy (anonymous):
I'm just confused on what to do after the product rule
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OpenStudy (abdullah1995):
alright i am going to give you a link for virtual whiteboard. go on it and i will explain it to you over there
OpenStudy (anonymous):
I got it to \[2x(2x+1)+\frac{ 1 }{ 2 }(2x+1)^{\frac{ -1 }{ 2 }}(2)(x ^{2)}\]
OpenStudy (anonymous):
would that be correct?
OpenStudy (abdullah1995):
lets see
OpenStudy (abdullah1995):
no that is wrong.
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OpenStudy (abdullah1995):
the answer is 2x(2x+1)^(1/2) + (x^2)*(2x+1)^(-1/2)