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Mathematics 13 Online
OpenStudy (anonymous):

what is the derivative of x^2(2x+1)^(1/2)

OpenStudy (anonymous):

\[x ^{2}(2x1)^{1/2}\] This is the equation

OpenStudy (anonymous):

(2x+1)

OpenStudy (anonymous):

yes that is the equation

OpenStudy (anonymous):

Do you know the product rule?

OpenStudy (anonymous):

yes I do

OpenStudy (anonymous):

OK so we are looking at x^2 times (2x+1) ^ 1/2 correct?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

would I use the product rule?

OpenStudy (abdullah1995):

this is a simple product rule question. if you want, expand it all out so it becomes a power rule

OpenStudy (anonymous):

Yes use the product rule.

OpenStudy (abdullah1995):

product rule = f'(g)(fx)+f(g)f'(x)

OpenStudy (abdullah1995):

in this case x^2 => f(g) (2x+1)^(1/2) =>f(x)

OpenStudy (anonymous):

oh ok thank you so much!

OpenStudy (abdullah1995):

if you are still having trouble let me know and we can go over it step by step

OpenStudy (anonymous):

I'm just confused on what to do after the product rule

OpenStudy (abdullah1995):

alright i am going to give you a link for virtual whiteboard. go on it and i will explain it to you over there

OpenStudy (anonymous):

I got it to \[2x(2x+1)+\frac{ 1 }{ 2 }(2x+1)^{\frac{ -1 }{ 2 }}(2)(x ^{2)}\]

OpenStudy (anonymous):

would that be correct?

OpenStudy (abdullah1995):

lets see

OpenStudy (abdullah1995):

no that is wrong.

OpenStudy (abdullah1995):

the answer is 2x(2x+1)^(1/2) + (x^2)*(2x+1)^(-1/2)

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