Mathematics
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OpenStudy (anonymous):
Can someone please help me, i just need this question to earn an 100 in my homework:( i don't get it at all
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OpenStudy (anonymous):
OpenStudy (anonymous):
calculate where 2nd deriv is equal to 0
OpenStudy (anonymous):
i did !!!
OpenStudy (anonymous):
wait no i didn't i don't get how with trigonometry involved
OpenStudy (anonymous):
i know how to deriv but not these kind
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OpenStudy (anonymous):
derivative of sin is cos
derivative of cos is -sin
OpenStudy (anonymous):
so f'(x) = 5cos(x) -5sin(x)
f"(x) = -5sin(x) - 5cos(x)
OpenStudy (anonymous):
so then, where, from 0 to 2pi, does f"(x) = -5sin(x) - 5cos(x) = 0?
OpenStudy (anonymous):
if x<0 or x>2pi, it doens't count
OpenStudy (anonymous):
yea i knew that, but how do i put it in terms of webassign?
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OpenStudy (anonymous):
what values did you get for x?
OpenStudy (anonymous):
yea, we exclude that part!! okay:)
OpenStudy (anonymous):
no i meant i knew that sin derived is cos
OpenStudy (anonymous):
so, what value of x satisfies:
-5sin(x) - 5cos(x) = 0
OpenStudy (anonymous):
none, like with my other problems i would just factor after getting the 2nd derivative and then get the values from there
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OpenStudy (anonymous):
do u get what im saying?
OpenStudy (anonymous):
OpenStudy (anonymous):
thats how i did all my other examples
OpenStudy (anonymous):
trigonomic functions are a bit different from polynomials like x^2-4=0
OpenStudy (anonymous):
these values from 0, 2pie
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OpenStudy (anonymous):
yea, no wonder i can't do it and keep getting it wronG:/
OpenStudy (anonymous):
well, we do some more algebra so we get sin(x)/cos(x) = 0
OpenStudy (anonymous):
sin(x)/cos(x) is tan(x)
OpenStudy (anonymous):
yes, identities are being used right?
OpenStudy (anonymous):
so find when tan(x) = 0 between 0 and 2pi
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OpenStudy (anonymous):
er tan(x) =1
OpenStudy (anonymous):
not tan(x) = 0
OpenStudy (anonymous):
tan is simply sin over cosine so i just look for those values? im sorry im really bad at trig
OpenStudy (anonymous):
actually tan(x) = -1
OpenStudy (anonymous):
can u explain why please?
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OpenStudy (anonymous):
you can undo the tan function with the arctan aka\[\tan^{-1} \]function
OpenStudy (anonymous):
so \[\tan^{-1}( \tan (x)) = \tan^{-1} (-1)\]which becomes\[x = \tan^{-1} (-1)\]
OpenStudy (anonymous):
you can look up values on a trig table
OpenStudy (anonymous):
okay yea i see!!! thank you for going through steps with me
OpenStudy (anonymous):
so then after that?
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OpenStudy (anonymous):
plug the values you got back into the f(x), the original equation
OpenStudy (anonymous):
the -1?
OpenStudy (anonymous):
i dont get the steps at all im sorry i dont get this problem at all, i mean after you do it it makes sense but that all