ok can someone help me with this problem ill post the link

Question

anonymous · Answer

there is a solution to this problem i just don't know why i can't get the correct one

unklerhaukus · Answer

first factor the denominator of the fraction on the left hand side

anonymous · Answer

which would be 3(x-3)

anonymous · Answer

and x-3 is already factored

unklerhaukus · Answer

yeah

so you have

x/(3x-9) -3= 1/(x-3)
x/(3(x-3)) -3= 1/(x-3)

now multiply both sides by   (x-3)

anonymous · Answer

ok what would you get because I'm getting a really big equation so i must have made some sort of mistake

unklerhaukus · Answer

x/(3(x-3))*(x-3) -3*(x-3)= 1/(x-3) *(x-3)
x/3                    -3*(x-3) = 1

anonymous · Answer

ok so you would get x/3-3(x-3)=1

anonymous · Answer

then what would you do?

unklerhaukus · Answer

now expand    -3(x-3)

anonymous · Answer

so -3x+9 correct?

unklerhaukus · Answer

yeah so you now have 

x/3-3(x-3)=1
x/3-3x+9=1

to solve for x 

take away 9 from both sides, 

then multiply both sides by 3

anonymous · Answer

ok so i did that and i ended with the answer of x=3 is that correct or did I make a mistake?

anonymous · Answer

i don't believe it plugs back into the original formula so i think i made  a error

unklerhaukus · Answer

well, that is right result, 

but what happens when we try to plug this into the original equation

x/(3x-9) -3= 1/(x-3)

plugging in x=3

x/(3*3-9) -3= 1/(3-3)
                    =

unklerhaukus · Answer

***

plugging in x=3

3/(3*3-9) -3= 1/(3-3)
                    =

unklerhaukus · Answer

what do those denominators become?

anonymous · Answer

zero which you can't divide by

anonymous · Answer

so would there be a answer according to the problem it has a solution but it marks 3 as wrong

unklerhaukus · Answer

exactly, the solution we found is unmathematical 

(dividing by zero is illegal)   ->   there are no solutions

anonymous · Answer

ok then the problem is wrong then because it has 2 parts it says does the problem have a solution I first said no it marked that as wrong but then i did yes and it marked it correct so I'm confused you think the software is wrong or something ?

unklerhaukus · Answer

As we have shown, there are no solution, perhaps the software is error,

anonymous · Answer

ok thanks for the help I'm going to email the professor about it maybe it has a glitch

unklerhaukus · Answer

that is a good idea, 

see you next time