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Estimate the value of 17^(1/4) using differentials??!!???
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Please show the steps
Use google.
I google it for you, hold on.
actually I can't sorry, I have no idea what differentials are.
say \(\large y = x^{1/4}\) and suppose your starting value is x = 16
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then dx = 1, yes ?
\(\large y = x^{1/4} \implies dy = \frac{1}{4}x^{-3/4} dx\)
plugin x = 16 and dx = 1 above ^^
ganeshie8. why does dx=1? I don't see how you got that value
we have assumed our starting value is x=16 because 16^(1/4) = 2, which is easy to compute dx = 17-16 = 1
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dx is the difference between final value of x and the starting value
THANKS!
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