Question

HELP!!!!! A plane moves at a certain velocity and then accelerates at the rate of 52m/s^2 for a distance of 2300m to reach a velocity of 620m/s. How fast was the plane going before it began to accelerate?

Answer 1

are you studying mechanics?

Answer 2

its for my physics class

Answer 3

do you have an equation that doesn't use time?

Answer 4

here you need to find the initial velocity

Answer 5

uhh yea...its vf^2=vi^2+2ad

Answer 6

ok so u need to use the eqn:
\[v ^{2}= u ^{2}+2as\]

Answer 7

yup

Answer 8

so 620=vi^2+2(52)(2300)

Answer 9

i mean 620^2

Answer 10

so 38440=vi^2+239200

Answer 11

so then square root of 145200
which is 381.05 m/s

Answer 12

which is my answer right?

Answer 13

yup

Answer 14

THANKS! :)