Question

In a box there are 6 red, 5 green and 4 white balls. If four balls are selected at random and the color noted, find the probability that none are green given that none are white.

Answer 1

i know the answer if that helps, i just need to know how to do it

Answer 2

given that none are white ... so forget all the white balls.

there are 6 red, 5 green balls. 4 balls are selected at random... Find the probability that none are green. ... that means find the probability that all are Red.
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Answer 3

6/11?

Answer 4

6/11 i the probability of the first ball you pick

what's the probability for the next ball

Answer 5

does it have to be red?

Answer 6

yes' all 4 have to be red since none are green

Answer 7

okay, so i THINK ... 5/10

Answer 8

right ...

Answer 9

if right then 1/2

Answer 10

then 4/9 for the next and 3/8 for the fourth ball

Answer 11

do you add or multiply?

Answer 12

So you answer should be : \[\Large {6 \over 11} \times{5 \over 10} \times{4\over9} \times{3\over8}\]

Answer 13

1/22 thanks :)