Question

solve z^2+2jz+14-8j+0, where j is imaginary

Answer 1

That should be = 0**

Answer 2

Is z real or complex?

Answer 3

Assuming z is complex, you can either make the substitution that \[\LARGE z=a+bi\] or \[\LARGE z=re^{i \theta}\] and try solving it this way. I chose the first way.

This gives you an equation with a bunch of real and imaginary stuff added together. You can separate the two equations though into the real and imaginary parts since just like a basket full of apples and oranges, you can take all the oranges out and the equality in the basket of apples remains unchanged.

Answer 4

is the plus sign = ?

Answer 5

z^2+2jz+14-8j=0

Answer 6

why dont you use quadratic formula ?

Answer 7

fyi, you can edit your question

Answer 8

Using quadratic formula I get
z = 1 + 3j
z = -1 -5j

Answer 9

Yeah i rearranged it and used the quadratic formula, thanks gang!!!