I´m trying to solve this question. What I need is to find the coordinates (0, 4l/3,0). There´s a picture of some part of my work.

Question

anonymous · Answer

attachment

boldjon · Answer

no offence but that handwriting is just.....

anonymous · Answer

Good. lo/

anonymous · Answer

$$x^2+\left( y-\frac{ 4l }{ 3 } \right)^2+z^2-\left( \frac{ 4l }{ 3 } \right)^2+\frac{ 4l^2 }{ 3 }=0$$

loser66 · Answer

From your work, you have $3x^2 +3y^2-8ly + 3z^2 =-4l^2$
Then you plug (0, 4l/3, 0) into it , you will get $4l^2 -112l=0$, solve for l, you have 2 values of l, those are $l =0, l =28$
Hence, with those values of l, your equation have the point (0,4l/3,0) is on the graph.