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Computer Science 8 Online
OpenStudy (anonymous):

logic question in post

OpenStudy (anonymous):

see the picture why this is true if we changed the direction of implies?

OpenStudy (anonymous):

If it is tru that For all y there exists an x such that some function P(x,y) is true this does not imply that There exists an x so that for All y the function P(x,y) is true for instance P(x,y) is x>y, then For all y a value of x can be found such that x>y but it is not true that There exists a x such that fo All y, x>y since there is no such thing as a biggest number

OpenStudy (anonymous):

OK thanks a lot man but this methodology is induction right?

OpenStudy (anonymous):

I don't think so Induction is for example base case x = 1, something is true for x = 1 x = n, something is true for x = n Hence it is true for x = n+1, or for all ix but you could use that for prove both statements, but I don't see how to apply it to the implication (the combination of those statements, that is)

OpenStudy (anonymous):

one more question please Can explain the same example for its converse?

OpenStudy (anonymous):

I don't think you use induction to disprove something It is usually easier to have a counter example

OpenStudy (anonymous):

I don't understand what you mean by its convers, what should that be?

OpenStudy (anonymous):

There exists an x so that for All y the function P(x,y) is true This implies that all y there exists an x such that some function P(x,y) is true why this implies? with the same example x>y

OpenStudy (anonymous):

@abtster

OpenStudy (anonymous):

Well, x>y is not a good example for this, it cannot be the function P Let me think of a better example hang on

OpenStudy (anonymous):

Hey man i need this example as i can't see the difference between both cases

OpenStudy (anonymous):

say P x > - y^2

OpenStudy (anonymous):

If there is an x such that for all y P is true therefore for all y there exists an x such that P is true Yes I think this is true for all valid functions P

OpenStudy (anonymous):

OK why didn't we use the example of x>y !!!

OpenStudy (anonymous):

If it were not true, then there would not be any x and the first part would not be true

OpenStudy (anonymous):

For that function the first statement is not true and implications of false statements are not valid (they can be true or untrue, but not based on the first statment The statement There is an x such that for all y, x>y is not true So that function cannot be used as an example

OpenStudy (anonymous):

why this statement( all y there exists an x) is true ?

OpenStudy (anonymous):

it is only true for functions that work, so not all functions are valid for that statement

OpenStudy (anonymous):

I think that is a bit of magic What is the most first step i would do to understand such statement?

OpenStudy (anonymous):

Putting it in words, like we did here, and try to understand the line Don forget any element That's how I do it

OpenStudy (anonymous):

Then, try to think of an example if there are any abstract elements, such as a general function like P(x,y) that might be the hardest bit

OpenStudy (anonymous):

OK thank you so much. I have to work it out. I will take a rest then see it again.

OpenStudy (anonymous):

Good luck

OpenStudy (anonymous):

@abtster Can you tell me if my understanding is right or not? Q.If there is an x such that for all y P ---> all y there exists an x such that P. A. so the equation is x = c (assuming it is true) and if i put any value of y that would give me x and its true.Thus it is valid. Q.all y there exists an x such that some function P(x,y) ---> There exists an x so that for All y the function P(x,y). A. the equation is y^0=1=c=x (assuming this is true ) .Thus if i knew x I can't predict Y. Excuse me,I am loading you (Did I get it or not).

OpenStudy (anonymous):

It had to be shown that the first Q is generally untrue. If you find one example of P that makes it untrue then Q is refuted Even if you can find an example that makes Q true in that particular example of P, that doesn't make Q true in generally true, it just happened to be true in that particular case

OpenStudy (anonymous):

An example of P can also make the thesis Q more clear, but doesn't in itself proof anything, a particular example can only disprove if Q is then false

OpenStudy (anonymous):

Maybe there is someone in mathematics who knows more about this subject and can explain it better than me

OpenStudy (anonymous):

I got it ,so I shouldn't use any example at the first Q ,but use p(x,y) as a general case. Thanks man I think I got it now :D

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