Question

@amistre64

Three employees work at a shipping warehouse. Tom can fill an order in
s minutes. Paco can fill an order S-2 in minutes. Carl can fill an order in s+1 minutes. When Tom and Paco work together, they take about
1 minute and 20 seconds to fill an order. When Paco and Carl work
together, they take about 1 minute and 30 seconds to fill an order.
a) How long does each person take to fill an order?
b) How long would all three of them, working together, take to fill
an order?

Answer 1

So u do 1x30 and get the answer for a

Answer 2

?

Answer 3

what is 30x1

Answer 4

30

Answer 5

you get 30 ok

Answer 6

lol that is not the answer...

Answer 7

for a at least

Answer 8

nope, how long does each employee take to fill one order. 30 is not the answer

Answer 9

well then idk

Answer 10

what equations can we form with the given information in the problem ...

Answer 11

thats actually what i'm having trouble with, I don't know how to go about forming the equation

Answer 12

well we know s is the time tom takes fill an order, and paco take 2 min less and carl takes 1 min more.

Answer 13

we are given that
t = this
p = that
c = another

then we are given that working together:

t+p = something
and
p+c = something else

so its all a matter of substitution

Answer 14

right.

Answer 15

letting t=s ...

t + (t-2) = 60+20

(t-2) + (t+1) = 60+30

Answer 16

i dint read minutes, and converted to seconds ...

Answer 17

60 + 20 seconds = 1 + 2/6 minutes

Answer 18

okay. so should i do elimination?

Answer 19

i don tthink its so much elimination anymore as simply solving for t

Answer 20

I got t=41

Answer 21

t + (t-2) min = 1+ 20/60

2t -2 = 1+ 20/60

2t = 3+ 20/60

t = 3/2+ 10/60 minutes

Answer 22

that does not make sense... cuz then paco will have a negative time.

Answer 23

hmm, is there an error in that?

Answer 24

yeah, i noticed

Answer 25

Someone else did this question, but i do not understand how they, did it, maybe you can explain it to me?
https://ca.answers.yahoo.com/question/index?qid=20101017101534AA8UA9t

Answer 26

it takes t and p 1,20 to finish a project

it takes p and c 1,30 to finish a project

by proportions

t/1,20 + p/1,20 = 1 project

assuming the same project

p/1,30 + c/1,30 = 1 project

somethings churning in there

Answer 27

oh i c

Answer 28

elimination would only be useful of we had 3 equations in 3 unknowns, but we have 2 equations in 3 unknowns

Answer 29

I'm stumped on this question, hmm

Answer 30

I dont understand why the person who solved this did this 1/s + 1/(s - 2) = 1/(4/3) = 3/4

Answer 31

im not so sure why the did either ... if its accurate then its by some other method that they are more comfortable with

Answer 32

s/1,20 + (s-2)/1,20 = 1 project

(s-2)/1,30 + (s+1)/1,30 = 1 project

s/1,20 + (s-2)/1,20 = (s-2)/1,30 + (s+1)/1,30

s/1,20 + s/1,20 -2/1,20 = s//1,30 -2/1,30 + s/1,30 +1/1,30

s/1,20 + s/1,20 -2/1,20 = s//1,30 -2/1,30 + s/1,30 +1/1,30

Answer 33

http://www.wolframalpha.com/input/?i=x%2F%281%2B2%2F6%29+%2B+x%2F%281%2B2%2F6%29+-2%2F%281%2B2%2F6%29+%3D+x%2F%281%2B3%2F6%29+-2%2F%281%2B3%2F6%29+%2B+x%2F%281%2B3%2F6%29+%2B1%2F%281%2B3%2F6%29

lol, im getting s=5

Answer 34

Still does not make sense, i guess im just going to have to ask my teacher how to go about solving this question. Thanks for having a look at it.

Answer 35

t=5, p=3, c=6

but not this seems odd to me as well. srry, i cant seem to think straight on this one

Answer 36

t takes s minutes to do 1 job; the amount of the job per minutes is therefore: 1/s of the job each minute

p take s-2 mintes to do 1 job, the amount of a job that p gets done in 1 minutes is thereofre 1/(s-2)

c takes ... same concept

this is better

Answer 37

oh ic you put it into a rate.

Answer 38

yes, finding a unit rate is important so that we can standardize their work efforts

Answer 39

i wonder if calculus would help :) id prolly mess it up if i tried rates of change

Answer 40

to do one job,
\[t+p = 8/6~min \]
so in 1 minute they can do 6/8 of the job the unit rate

Answer 41

\[\frac{ 1 }{ s }+\frac{ 1 }{ s-2 }=\frac{ 4 }{ 3 }\]

I think then 4/3 become 3/4 since what ever we do to one side we do to the other, correct me if im wrong.

Answer 42

4/3 is not a unit rate, its a total time frame like s or s-1

we want a unit rate for comparison so 3/4 is what we are looking for i believe

Answer 43

well then, now everything works out. and i got s=4

Answer 44

so it take tom 4min, paco 2min, and carl 5min.

Answer 45

then they can do 1/4 and 1/2 and 1/5 of a job per minute

1/4 + 1/2 = 3/4 of the job in 1 minute i like it

Answer 46

Alright thanks for helping with this abomination of a question lol.

Answer 47

4/3 (1/4 + 1/2) = 1 job

(1/3 + 2/3) = 1 job in 4/3 minutes

Answer 48

i swear this is simple enough to accomplish when you recall what to do lol