Ask
your own question, for FREE!
Mathematics
14 Online
arctan(x)/sqrt(x) dx
Still Need Help?
Join the QuestionCove community and study together with friends!
\[\int\limits_{}^{}x^\frac{-1}{2} \arctan(x) dx\] let u=sqrt(x) so u^2=x so 2udu=2x so we have \[\int\limits_{}^{}u^{-1} \arctan(u^2) 2u du \] u^(-1)*u=1 So anyways now I would do integration by parts.
But that still may not be the easiest way...
i wonder if this was meant to be definite integral instead...
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours!
Join our real-time social learning platform and learn together with your friends!
Join our real-time social learning platform and learn together with your friends!
Latest Questions
Aubree:
Guys, what does love feel like? I've been getting a tight chest and when I talk to him my heart rate hangs out around 100-120 beats per min, and when he doe
thereneelg:
ok... anyone have advice?? ...I did Choir all throughout Middle school and have ALWAYS been put in Soprano those three years.
kamariana:
The Byzantine Procopius is known for (5 points) reconquering much of the old Roma
chuckD:
hellp!!! what does it mean to describe a scientist as skeptical Why is sceptical
DoltonCarlee:
So like do y'all know anything about the first world war?
thehearken:
anyone know how to explain this so its easier for me to understand? b(1)=2, b(n)=
8 hours ago
8 Replies
1 Medal
1 day ago
6 Replies
1 Medal
2 days ago
0 Replies
0 Medals
2 days ago
2 Replies
1 Medal
1 day ago
2 Replies
0 Medals
1 day ago
5 Replies
2 Medals