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arctan(x)/sqrt(x) dx
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\[\int\limits_{}^{}x^\frac{-1}{2} \arctan(x) dx\] let u=sqrt(x) so u^2=x so 2udu=2x so we have \[\int\limits_{}^{}u^{-1} \arctan(u^2) 2u du \] u^(-1)*u=1 So anyways now I would do integration by parts.
But that still may not be the easiest way...
i wonder if this was meant to be definite integral instead...
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