are medians of . If AG = (x + 5) in. and GD = (x – 1) in., what is the length of ? A. 6 in. B. 10 in. C. 12 in. D. 18 in.
*kisses u*
what
cant help it ur too beautiful
uuhh thank you
need more info
it a triangle |dw:1413496939281:dw|
your question is incomplete though
maybe you could take a picture of the problem and upload it
AD , BE, AND CF are median of ABC
ok so AG = 2/3 * AD
x+5 = 2/3 * ( x + 5 + x - 1 )
it is asking for th length of gd
since AD = AG + GD AG = 2/3 * (AG + GD )
now substitute
I am using the centroid theorem , (the centroid is 2/3 the length from the vertex to the midpoint of the opposite side)
so it is 18?
you need to first find x
the answer is GD = 6, actually
since AD = AG + GD (segment addition postulate) and because AG = 2/3 * (AD) centroid theorem so putting it together AG = 2/3 * ( AG + GD) AG = 2/3 * AG + 2/3*GD AG - 2/3*AG = 2/3 * GD 1/3*AG = 2/3*GD multiply both sides by 3 AG = 2*GD now substitute x+5 = 2 (x-1)
thank you
so x + 5 = 2x - 2 7 = x now GD = x -1 , so GD = 7-1 = 6
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