Question

What would be the restrictions of this problem?

(a+x)/(b-x)=c, x =/= b

the answer i get is x= (cb-a)/(c+1), the restrictions is that c cannot equal -1 AND x cannot equal b.

BUTTT my teacher said that we cant have x as part of the restriction answer. so we have to substitute the x in the restriction with the solution we get.

My question is when we substitute it, do we simplify it or solve for a variable??

Answer 1

Make sure the denominator is not zero (0).

Answer 2

i know you do that, but one of the restriction is x cannot equal b. but x cannot be part of restriction. so we subtitute x with the solution of x which is (cb-a)/(c+1) = b
for this, do we simplify or solve for a variable to get the new restriction?

Answer 3

anyone?

Answer 4

Sorry, but that makes little sense. In the general convention of things, a, b, and c are KNOWN parameters. They can't be or not be anything. They are what they are. I really would like to know what your objectionable teacher is talking about.

\(x\ne b\) does not contain 'x' in the definition. The definition is "\(\ne b\)". I don';t see an 'x' in there.

Answer 5

idk, she says she doesn't want x to be a restriction in our solutions.

Answer 6

Soooo,she tells us to substitute x with something else. Also, we only have to do these for literal equations.

Answer 7

Love to see an example.

Answer 8

another exampleis a=(b+cx)/(dx),dx =/=0

dx=/=0 cannot be part of restriction we when solve for x. The answer to the example cannot be {x;x= b/(ad-c), dx=/=0, ad=/=0} because x is in the restriction.

Therefore we must substitute x in dx=/=0 with the solution x is equal to which is b/(ad-c)

so d(b/(ad-c))=/=0

and then im stuck from here