find the value for K so that the line through the given points are parallel line 1: (-5,-2)& ( 0,0) line 2: (1,6) & (k,7)
what's the slope of the 1st one anyway? any ideas? bear in mind tha parallel lines have the SAME SLOPE
the slope for the first line is 2/5
so.... yeap is 2/5 so now we know that so we use that slope for the 2nd line then thus \(\bf \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ &({\color{red}{ 1}}\quad ,&{\color{blue}{ 6}})\quad &({\color{red}{ k}}\quad ,&{\color{blue}{ 7}}) \end{array} \\\quad \\ slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ 7}}-{\color{blue}{ 6}}}{{\color{red}{ k}}-{\color{red}{ 1}}} =\cfrac{2}{5}\) solve for "k"
wooops darn wrong window... lemme remove that =(
ok
i got it thanks
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