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Mathematics 11 Online
OpenStudy (anonymous):

Graphing Will award medal !

OpenStudy (anonymous):

OpenStudy (anonymous):

@Nnesha @Compassionate @robtobey Help please :)

OpenStudy (anonymous):

I really need help

OpenStudy (anonymous):

@jim_thompson5910 Help please !:)

OpenStudy (anonymous):

@amistre64 Can you help me please :)

jimthompson5910 (jim_thompson5910):

focus on each piece individually

jimthompson5910 (jim_thompson5910):

is y = 2-x continuous?

OpenStudy (anonymous):

Yes

jimthompson5910 (jim_thompson5910):

how about y = x^2 ?

OpenStudy (anonymous):

No , its a parabola right

OpenStudy (anonymous):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

why wouldn't it be continuous?

jimthompson5910 (jim_thompson5910):

all parabolas are continuous

OpenStudy (anonymous):

Okay

jimthompson5910 (jim_thompson5910):

how about the last piece?

OpenStudy (anonymous):

Yes it is

jimthompson5910 (jim_thompson5910):

now focus on each junction

jimthompson5910 (jim_thompson5910):

let's say we have these three functions f(x) = 2-x g(x) = x^2 h(x) = 6+x

jimthompson5910 (jim_thompson5910):

when the first 2 pieces connect, f and g, they connect at the junction x = -2 if and only if f(-2) = g(-2)

jimthompson5910 (jim_thompson5910):

what are f(-2) and g(-2) ?

OpenStudy (anonymous):

The function ?

jimthompson5910 (jim_thompson5910):

f(-2) = ??

OpenStudy (anonymous):

f(-2) = 2-(-2)

jimthompson5910 (jim_thompson5910):

simplify that

OpenStudy (anonymous):

f(-2)=4

jimthompson5910 (jim_thompson5910):

what is g(-2)

jimthompson5910 (jim_thompson5910):

what is it equal to

OpenStudy (anonymous):

g(-2)=4

jimthompson5910 (jim_thompson5910):

so that proves the two functions f(x) and g(x) connect at x = -2

jimthompson5910 (jim_thompson5910):

here is visual proof of that

OpenStudy (anonymous):

Okay so now i find the range of that

OpenStudy (anonymous):

What about the third function

jimthompson5910 (jim_thompson5910):

you have to determine if the second piece (g(x)) connects to the third piece (h(x))

jimthompson5910 (jim_thompson5910):

use the same basic idea you used before (when you showed how f(x) and g(x) connect)

OpenStudy (anonymous):

so h(-2)=4

jimthompson5910 (jim_thompson5910):

we're not at x = -2 anymore

jimthompson5910 (jim_thompson5910):

notice how the junction between g(x) and h(x) is at x = 3

jimthompson5910 (jim_thompson5910):

I'll be right back

OpenStudy (anonymous):

Wait this expires in like half an hour please

OpenStudy (anonymous):

My assignmet expires soon

OpenStudy (anonymous):

h(3)=9

OpenStudy (anonymous):

h(3)=9

OpenStudy (anonymous):

Is that right

jimthompson5910 (jim_thompson5910):

h(3) = 9, yes

jimthompson5910 (jim_thompson5910):

g(3) = ???

OpenStudy (anonymous):

g(3)=9

jimthompson5910 (jim_thompson5910):

so that proves g(x) and h(x) connect at x = 3

jimthompson5910 (jim_thompson5910):

This graph shows the graph is continuous everywhere

OpenStudy (anonymous):

Okay I see so now do we find the range or

jimthompson5910 (jim_thompson5910):

we don't need to find the range

jimthompson5910 (jim_thompson5910):

they don't ask for that

OpenStudy (anonymous):

Oh ok well how do i put this in set notation?

jimthompson5910 (jim_thompson5910):

they want the answer in interval notation

OpenStudy (anonymous):

Yeah its in the attachment

jimthompson5910 (jim_thompson5910):

how do we say "the set of all real numbers" in interval notation?

OpenStudy (anonymous):

(- infinity , infinity)

jimthompson5910 (jim_thompson5910):

that's your answer

OpenStudy (anonymous):

YES IT WAS RIGHT THANK YOU SO MUCH FOR ALL YOUR HELP !! :D

jimthompson5910 (jim_thompson5910):

np

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