PLEASE HELP!!!
What would you like to know?
i dont know how to solve the equation because theres a fraction. @jasonjohnson86
\[f(x) = -\frac{ 1 }{ 2 } x² - 2x -3\] you could write it as \[f(x) = -\frac{ x² }{ 2 } - 2x -3\] or \[f(x) = -0.5 x² - 2x -3\] Does that help?
Do you need to calculate where the maximum is and the zero points?
If you divide by a fraction then you multiply by the reverted fraction So the top is at \[x = \frac{ -b }{ 2a}\] right? so, fill them in a = -1/2 , and b = -2
multiplying by a half is like dividing by 2
the 2 should not have negative
so the answer would be -1?? @abtster
i mean my symmetry is -1??
sorry, I was distracted the - is like multiplying by -1 -1*-1 = 0 right?
im talking about the b=-2
how much is two halves? 1 right? So 2a = 2*(-1/2) = -1 indeed! x = -b/2a = (-1*-1*2)/(-1) =
@abtster -1*-1=1
not 0....
yeh, sorry, thatś what I meant
x = -b/2a = (-1*-1*2)/(-1) = (1*2)/(-1)
so 1 is my axis symmetry?? @TheSmartOne
dividing by -1 is the same as multiplying by it x = =b/2a = -2 yes, thats your axis and where the top is
Vertex=(x,y) \[x=-\frac{ b }{ 2a}\] \[y=f(-\frac{ b }{ 2a })\]
Now you probably wont the zero points
@TheSmartOne how come my axis of symmetry is on the -2??
\[x=\frac{ -(-2) }{ 2\times \frac{ -1 }{ 2 } }=\frac{ 2 }{ -1 }=-2\]
We are calculating the vertex not the axis of symmetry...
@TheSmartOne did you use the formula -b/2a to get -2??
Now to find y we plug back in -2 \[f(x) = -\frac{ 1 }{ 2 } (-2)² - 2(-2) -3\] \[f(x)=-2+4-3\]
you forgot to square the -2
I squared it and got 4 and that divided by -2 =-2
@clamin Yes I did use the formula to get -2..
So yea continue on -2+4-3=-1 So the vertex is (-2,-1)
@clamin
The problem was how to deal with fractions I think Clamin can do deal with it now
Join our real-time social learning platform and learn together with your friends!