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Hydrazine reacts with dinitrogen tetroxide according to the equation: 2N2H4 + N2O4 = 3N2 + 4H2O? 50.0 grams of hydrazine is mixed with 100.0 grams of dinitrogen tetroxide. How much nitrogen gas was produced?
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You have 1.56 mol of N2H4 and 1.09 mol of N2O4, therefore N2H4 is your limiting reactant. To solve for how many moles of N2 was produced set up the proportion: (1.56 mol N2H4) (3 mol N2/2 mol N2H4) You can cross out the "mol N2h4" and you're left with 2.34 mol of N2 which should be the answer.
then multiply by 28 to find the grams right?
Yes.
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