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OpenStudy (anonymous):
A pharmacist prepares a medicine by mixing 286 g of CaCo3 and 150 g of glycine (C2H5NO2) in water, and then completely drying the mixture. What is the mas% of carbon in the final medicine?
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OpenStudy (anonymous):
286g of CaCO3 (100g/mol) so 2.86 moles 150g of C2H5NO2 (75g/mol) so 2 moles 2 moles of C2 is 24 grams 2.86 moles of C is 34.32 grams total 58.32 grams 58.32/(286+150) = 0.134
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