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Mathematics 16 Online
OpenStudy (anonymous):

In an 8.00km race, one runner runs at a steady 11.5km/h and another runs at 14.9km/h.

OpenStudy (anonymous):

How far from the finish line is the slower runner when the faster runner finishes the race?

OpenStudy (skullpatrol):

any ideas?

OpenStudy (anonymous):

nope

OpenStudy (skullpatrol):

have you seen the distance formula: Distance = rate X time?

OpenStudy (skullpatrol):

Distance traveled = rate X time traveled

OpenStudy (anonymous):

ok let me try something

OpenStudy (anonymous):

rate is speed right?

OpenStudy (skullpatrol):

yes

OpenStudy (anonymous):

so time=distance/rate..time=8.00km/11.5km/h=92

OpenStudy (skullpatrol):

0.69565217391 h

OpenStudy (anonymous):

ya i just recalculate it and got the same answer...ok now i need its distance?

OpenStudy (skullpatrol):

Reread the problem and find out what the question is asking for.

OpenStudy (anonymous):

where the slowest guy at when the faster guy cross the finish line

OpenStudy (skullpatrol):

So find out how long it takes the faster guy to cross the finish line and then use that time to find out where the slower guys is, right?

OpenStudy (anonymous):

do i subtract the two hours?

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

ok so 8.00km/14.9km/h=.5369127517

OpenStudy (anonymous):

then now what?

OpenStudy (skullpatrol):

use that time to find out where the slower guys is, right?

OpenStudy (anonymous):

ok so now d=r*t

OpenStudy (anonymous):

d=.5369127517*11.5

OpenStudy (skullpatrol):

Yes, now answer what the question is asking for.

OpenStudy (anonymous):

6.174496644

OpenStudy (skullpatrol):

How far from the finish line is the slower runner when the faster runner finishes the race?

OpenStudy (skullpatrol):

Remember the race is 8.00km long

OpenStudy (anonymous):

he's at 6.17km right

OpenStudy (skullpatrol):

yes

OpenStudy (anonymous):

ok thanks

OpenStudy (skullpatrol):

How far from the finish line is the slower runner?

OpenStudy (anonymous):

1.83km

OpenStudy (skullpatrol):

correct :-)

OpenStudy (anonymous):

A pole-vaulter is nearly motionless as he clears the bar, set 4.2m above the ground. He then falls onto a thick pad. The top of the pad is 80 cm above the ground, and it compresses by 50cm as he comes to rest.What is his acceleration as he comes to rest on the pad?

OpenStudy (anonymous):

so i convert the 80 cm into .8m

OpenStudy (skullpatrol):

post this as another question please

OpenStudy (anonymous):

sry im new here

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