Consider the integral ∫2,0∫sqrt(4−y),0f(x,y)dxdy. If we change the order of integration we obtain the sum of two integrals:
∫ba∫g2(x)g1(x)f(x,y)dydx+∫dc∫g4(x)g3(x)f(x,y)dydx
a= b=
g1(x)= g2(x)=
c= d=
g3(x)= g4(x)=

Question

Consider the integral ∫2,0∫sqrt(4−y),0f(x,y)dxdy. If we change the order of integration we obtain the sum of two integrals:
∫ba∫g2(x)g1(x)f(x,y)dydx+∫dc∫g4(x)g3(x)f(x,y)dydx 
a=  b=  
g1(x)=  g2(x)=  
c=  d=  
g3(x)=  g4(x)=

hartnn · Answer

can you plot the region ? 

x= 0 to x = sqrt (4-y)
y =0 to y = 2

anonymous · Answer

i did...trying to get the image.  give me a second

hartnn · Answer

x= sqrt (4-y) 
will be the right half of parabola

x^2 = 4-y

hartnn · Answer

something like this ?
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