Question

Which equation has no solution?

a. 4(x + 3) + 2x = 6(x + 2)
b. 5 + 2(3 + 2x) = x + 3(x + 1)
c. 5(x + 3) + x = 4(x + 3) + 3
d. 4 + 6(2 + x) = 2(3x + 8)

Answer 1

the way i'd do it is to go one by one putting it in a mx+b form lemme do a for you

Answer 2

4(x + 3) + 2x = 6(x + 2)
4x+12+2x=6x+12 distribute the 4 on the left hand side then the 6 on RHS
6x+12=6x+12 add like terms

now since both sides are equal i think they have infinitely many solutions. SO you move on

Answer 3

to summarize
1. You distribute the number outside the parenthesis in both sides of the equation.
2. add the like terms in both sides of the equation
3. you will end up with something looking like mx+b on both sides


there are 3 possibilities. and keep in mind x is a variable

mx+b=mx+b same m and same b : infinite solutions
mx+b=Mx+b different m same b : one solution
mx+b =mx+B different b same m : no solution ANSWER

Answer 4

So the answer is

Answer 5

??

Answer 6

APply what i said to B C D

Answer 7

@mathmath333

Answer 8

you can do it just try B :)

Answer 9

Whats the answer

Answer 10

you wanna know how to do it or just want the answer?

Answer 11

the answer please

Answer 12

@dronchik

Answer 13

5 + 2(3 + 2x) = x + 3(x + 1)



\(\Large\tt \color{black}{4x+11=4x+3}\)


here if u substitute x=1

then

\(\Large\tt \color{black}{4+11=4+3}\)

\(\Large\tt \color{black}{15\neq7}\)

or if u substitute x=2

\(\Large\tt \color{black}{8+11=8+3}\)

\(\Large\tt \color{black}{19\neq11}\)

\(\tt \color{black}{\text{so due to contradiction this equation has no solution }}\)